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xxMikexx [17]
3 years ago
8

I need to draw an open shape made up of one or more curves

Mathematics
1 answer:
GalinKa [24]3 years ago
3 0
An open shape is made up of line segments. In this type of shape there is at least one line segment that is not connected to anything at one of its endpoints, so the shape is not a closed figure. So, I am going to provide four graphs for this problem.

1. Parable

This is given by the curve:

y=x^{2}

See figure 1.

2. Cubic function.

This function is given by:

y=x^{3}

see figure 2

3. Quartic function

This curve is given by:

y=x^{4}

see figure 3

4. Cosine function

This function is given by this equation:

y=cos(x)

See figure 4.

All these curves are open shapes. So, we can find a new open shape as the sum of all these curves as follows:

y=x^{2}+x^{3}+x^{4}+cos(x)

See figure 5.



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Answer:

A=189\ mm^2

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2

The front area is a rectangle of dimensions 7.7 mm and 9 mm, thus

A_f=b.h=(7.5)(9)=67.5 \ mm^2

The back left area is another rectangle of 4.5 mm by 9 mm

A_l=b.h=(4.5)(9)=40.5  \ mm^2

Finally, the back right area is a rectangle of 6 mm by 9 mm

A_r=b.h=(6)(9)=54 \ mm^2

Thus, the total surface area of the prism is

A=A_t+A_f+A_l+A_r=27+67.5+40.5+54=189\ mm^2

\boxed{A=189\ mm^2}

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2 years ago
Determine the slope and y-intercept of the line.<br> y = -69x - 346
Tpy6a [65]

Answer:

Slope: -69

Y-intercept: -346 or (0, -346)

Step-by-step explanation:

y = mx + b

    m = slope

    b = y-intercept

y = -69x - 346

    m = -69

    b = -346

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