M = 5/2
B = -4
Y - 1 = 5/2(x - 2)
Y - 1 = 5/2x - 5
+1. +1
Y = 5/2x - 4
(I think)
Since the quotient of the two decimal numbers is 1, that tells use that they are the same number.
Since the sum of the two numbers equals 1 and both numbers are the same, then the answer must be 1 divided by 2. or .5
the fractions would be 1/2 and 1/2
Answer:
![\frac{16 {d}^{3} }{ {c}^{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%20%7Bd%7D%5E%7B3%7D%20%7D%7B%20%7Bc%7D%5E%7B2%7D%20%7D%20)
Step-by-step explanation:
![{4}^{2} {c}^{ - 2} {d}^{3} {e}^{0}](https://tex.z-dn.net/?f=%20%7B4%7D%5E%7B2%7D%20%20%7Bc%7D%5E%7B%20-%202%7D%20%20%7Bd%7D%5E%7B3%7D%20%20%7Be%7D%5E%7B0%7D%20)
➡️ ![16 {c}^{ - 2} {d}^{3} \times 1](https://tex.z-dn.net/?f=16%20%7Bc%7D%5E%7B%20-%202%7D%20%20%7Bd%7D%5E%7B3%7D%20%20%5Ctimes%201)
➡️ ![16 {c}^{ - 2} {d}^{3}](https://tex.z-dn.net/?f=16%20%7Bc%7D%5E%7B%20-%202%7D%20%20%7Bd%7D%5E%7B3%7D%20)
➡️ ![16 \times \frac{1}{ {c}^{2} } \times {d}^{3}](https://tex.z-dn.net/?f=16%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B%20%7Bc%7D%5E%7B2%7D%20%7D%20%20%5Ctimes%20%20%7Bd%7D%5E%7B3%7D%20)
➡️ ![\frac{16 {d}^{3} }{ {c}^{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%20%7Bd%7D%5E%7B3%7D%20%7D%7B%20%7Bc%7D%5E%7B2%7D%20%7D%20)