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Harman [31]
2 years ago
11

5+2x15+1-6/76^3x2+73*0+0.0000273

Mathematics
1 answer:
NemiM [27]2 years ago
6 0
  • 6+2(15)+1-6/(76^2×2)+73×0+0.0000273
  • 6+30+1-6/11552+0+0.0000273
  • 37-0.000519+0.0000273
  • 36.999

Done

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I need help finding the answer
11111nata11111 [884]

Answer:

a

Step-by-step explanation:


8 0
3 years ago
12u + -8u = -20 solve for u
jekas [21]

u= -5

12u -8u=-20

4u=-20

u=-20/4

u=-5

hopes this helps,

Xeno

7 0
3 years ago
Read 2 more answers
Which expression is NOT equivalent to −38⋅(−4+12)? Drag this expression to the box.
lesya [120]

I had this question so here's the answer and explanation! :)

Answer:

The answer to your question is the first option :D

Step-by-step explanation:

Original expression

                                -3/8 (-4 + 1/2)

First option    -3/8 (-4)  + (3/8)(1/2)       This option is not equivalent because

                                                             they forgot the negative sign of the

                                                             second term.

Second option (-3/8)(-4) + (-3/8)(1/2)    This option is equivalent to the

                                                              original. Distributive property

Third option    (-3/2)(-3 1/2)                 This option is equivalent to the original

Fourth option  (-3/8)(-3) + (-3/8)(-1/2)  This option is equivalent to the original

HOPE THIS HELPS :)

5 0
3 years ago
Read 2 more answers
A compound experiment consists of drawing at random twice without replacing from a jar with 3 red, 3 white, and 2 black marbles.
Eddi Din [679]
The solution to your problem about the probability <span>of getting first a red and then a black marble is as follows:

</span><span>(3 red / 8 total) * (2 black / 7 total) = 3/28 
</span>
Therefore, the probability of getting first a red and then a black marble is 3/28.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
8 0
3 years ago
Suppose the scores on a test given to all juniors in a school district are normally distributed with a mean of 74 and a standard
ivann1987 [24]

Answer:

\mu -\sigma = 66 , \mu +\sigma = 82

\mu -2\sigma = 58 , \mu +2\sigma = 90

\mu -3\sigma = 50 , \mu +3\sigma = 98

And in the figure attached we see the limits with the percentages associated.

Step-by-step explanation:

For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

X \sim N(\mu= 74, \sigma =8)

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%

We can find the limits and we got:

\mu -\sigma = 66 , \mu +\sigma = 82

\mu -2\sigma = 58 , \mu +2\sigma = 90

\mu -3\sigma = 50 , \mu +3\sigma = 98

And in the figure attached we see the limits with the percentages associated.

7 0
4 years ago
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