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Ilia_Sergeevich [38]
3 years ago
15

What does this mean in python?

Computers and Technology
1 answer:
scoundrel [369]3 years ago
8 0

the comments in the code should explain everything, brainly's formatting might be weird


gate = raw_input("Enter logic gate :").upper()#.upper() so lower/upper case of input doesn't matter

firstInput = raw_input("Enter first input :")#raw_input() for python 2.7, input() for 3

secondInput = raw_input("Enter second input :")

if (firstInput!="0" and firstInput!="1") or (secondInput!="0" and secondInput!="1"):

print("inputs must be 0 or 1")#ensure all inputs are in boolean range

quit()


firstInput=firstInput=="1"#convert "1" to true and "0" to false

secondInput=secondInput=="1"


if gate=="AND" or gate=="NAND":

result=firstInput and  secondInput

elif gate=="OR" or gate=="NOR":

result=firstInput or secondInput

elif gate=="XOR":

result=firstInput!=secondInput

else:#handle case of unknown/mistyped gates

print(gate+" is not known")

quit()

if gate=="NOR" or gate=="NAND":

result=not result#invert result for nor and nand

print("Result = "+str(int(result)))#uses int so 1/0 are printed instead of True/False


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The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is :

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wariber [46]

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Explanation:

7 0
3 years ago
Given public class Fishing { byte b1 = 4; int i1 = 123456; long L1 = (long) i1; //Line A short s2 = (short) i1; //Line B byte b2
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Answer:

Line E.

Explanation:

The  given program is as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = b1 + 7;     //Line E

   }

In the above code Line E will not compile and give following compilation error:

error: incompatible types: possible lossy conversion from int to byte

This error is coming because in Java b1 + 7 will be interpreted as int variable expression. Therefore in order to make code of Line E work the expression should be type casted as byte.  

The correct code will be as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = (byte)(b1 + 7);     //Line E

   }

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