Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Hi!
When ever we start or restart any device we may hold - this process is called <em>booting. </em>
Hopefully, this helps! =)
Answer:
see explaination
Explanation:
//selective dev elements by id name
var gradeA = document.querySelector("#GradeA");
var passing = document.querySelector("#Passing");
var learning = document.querySelector("#Learning");
//function showGrades
function showGrades() {
var arr = [];
//converting string to int and inserting into array
arr[0] = parseInt(gradeA.textContent);
arr[1] = parseInt(passing.textContent);
arr[2] = parseInt(learning.textContent);
//creating json blob
var blob = new Blob(new Array(arr), {type:"text/json"});
return blob;
}
The answwer to the type of hardware is led lighting it does not need a inverter
