The answer would be option D.
10a^3 + 91a^2 + 54a - 792
Answer:
Step-by-step explanation:
Huhuj
First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them
12x^8/3x^3= 4x^8-3=4x^5
20^2x=20^x*20^x
m^5*m^-7=m^5-7=m^-2
Answer:
Brent’s club has more possible team combinations because there are more members to choose from
Step-by-step explanation:
Brents club can be created in C12 6 =12!/6!/6!=7*8*9*10*11*12/(2*3*4*5*6)=
=924 variants
Miguel's club can be created in C10 6=10!/6!/4!=7*8*9*10/(2*3*4)=210 variants
924>210 so Brent’s club has more possible team combinations because there are more members to choose from
