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jeyben [28]
3 years ago
13

What can you say about the past four decades?

Chemistry
1 answer:
Elis [28]3 years ago
5 0
The temperature of the globe has been ever increasing over the past 4 decades. We have also seen the rise of deforestation and etc. However, we have also seen advances in scientific technology that solves many complications. A very increasing field would be genetic modification or crispr and biomedical. Technology is also ever advancing into shaping the way we use gadgets. Internet access is no longer considered a privilege but a necessities to drive the economies running and keeping the nation economically stable. Many nations are now also heavily investing in space technologies for expedition to planet mars for the search of living things. In the past decades, renowned cosmologist Stephen Hawking has released many publications relating to Black holes etc. He had also went to talk about the existence of aliens and extraterrestial lifeforms and how the world may come to the end because of aliens. This is not a exhaustive lists of the events happened over the past 4 decades but it gives you brief through about the many contributions that the scientific community has given. Thus, this is all.
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Perform the following operation
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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:2.8 × {10}^{-5}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  \dfrac{2.36 \times 10 {}^{ - 2} }{8.4  \times {10}^{2} }

\qquad \tt \rightarrow \:  \dfrac{2.36  }{8.4   } \times  \cfrac{10 {}^{ - 2} }{10 {}^{2} }

\qquad \tt \rightarrow \:  0.28 \times 10 {}^{ - 2 - 2}

\qquad \tt \rightarrow \:  0.28  \times 10 {}^{  - 4}

\qquad \tt \rightarrow \: 2.8 \times 10 {}^{ - 5}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Explanation:

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Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea
galina1969 [7]

Answer:

Cd(s) + AgNO₃(aq)  → Cd(NO₃)₂ (aq) + Ag(s)

Oxidized: Cd

Reduced: Ag

Explanation:

Cd(s) + AgNO₃(aq)  → Cd(NO₃)₂ (aq) + Ag(s)

Cd → Cd²⁺  +  2e⁻      Half reaction oxidation

1e⁻ + Ag⁺ → Ag           Half reaction reduction

Ag changed oxidation number from +1 to 0

Cd changed oxidation number from 0 to +2

Let's ballance the electrons

( Cd → Cd²⁺  +  2e⁻ ) .1

( 1e⁻ + Ag⁺ → Ag ) .2

Cd + 2e⁻ + 2Ag⁺  → 2Ag +  Cd²⁺  +  2e⁻

Finally the ballance equation is:

Cd(s) + 2AgNO₃(aq)  → Cd(NO₃)₂ (aq) + 2Ag(s)

4 0
3 years ago
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