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jeyben [28]
3 years ago
13

What can you say about the past four decades?

Chemistry
1 answer:
Elis [28]3 years ago
5 0
The temperature of the globe has been ever increasing over the past 4 decades. We have also seen the rise of deforestation and etc. However, we have also seen advances in scientific technology that solves many complications. A very increasing field would be genetic modification or crispr and biomedical. Technology is also ever advancing into shaping the way we use gadgets. Internet access is no longer considered a privilege but a necessities to drive the economies running and keeping the nation economically stable. Many nations are now also heavily investing in space technologies for expedition to planet mars for the search of living things. In the past decades, renowned cosmologist Stephen Hawking has released many publications relating to Black holes etc. He had also went to talk about the existence of aliens and extraterrestial lifeforms and how the world may come to the end because of aliens. This is not a exhaustive lists of the events happened over the past 4 decades but it gives you brief through about the many contributions that the scientific community has given. Thus, this is all.
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Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.
Arada [10]

Answer:

X = 7

Explanation:

4 0
2 years ago
In a titration, 10.0 ml of 0.0750 M HCl(aq) is exactly neutralized by 30.0 ml of KOH(aq) of unknown concentration. What is the c
Sphinxa [80]

Answer: 0.0250

Explanation: 10 X 0.0750 = .75

.75 / 30 = 0.0250 M

4 0
4 years ago
How many moles of hydrogen are needed to completely react with 2 moles of nitrogen
Natali5045456 [20]
Assuming ammonia is the product of this reaction:

N2+3H2--->2NH3

2 mole N2 * (3 mol H2)/(1 mol N2)= 6 mol H2

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5 0
3 years ago
n unknown metal is either aluminum, iron or lead. If 150. g of this metal at 150.0 °C was placed in a calorimeter that contains
Nitella [24]

Answer : The metal used was iron (the specific heat capacity is 0.449J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of unknown metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of unknown metal = 150 g

m_2 = mass of water = 200 g

T_f = final temperature of water = 34.3^oC

T_1 = initial temperature of unknown metal = 150.0^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC

c_1=0.449J/g^oC

Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).

Therefore, the metal used was iron (the specific heat capacity is 0.449J/g^oC).

6 0
4 years ago
A 5.00 gram sample of water is heated so that its temperature increases from 10.0°C to 15.0°C. What is the
tresset_1 [31]

Answer:

15.0°C

Explanation:

hope it helps

3 0
3 years ago
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