Question

is it possible for a balloon with an initial pressure of 200.0 kpa to naturally expand to four times its initial volume when the temperature remains constant and atmospheric pressure is 101.3 kPatial

Answer 1

Answer: No, it is not possible.

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$     (At constant temperature and number of moles)

$P_1\times V_1=P_2\times V_2$

where, $P_1$= initial pressure = 200 kPa

$V_1$= Initial volume = v

$P_2$= initial pressure = 101.3 kPa

$P_1\times V_1=P_2\times V_2$

$200\times v=101.3\times V_2$

$V_2=2v$

Thus the final volume can only be twice of original volume. If it is greater than that, the balloon will burst.

Answer 2

You can find the ratio that it can expand with the atmospheric pressure.

200.0/101.3= 1.97 ≈ 2, this means that the balloon could expand twice its initial volume. So, it is not possible for the balloon to expand to 4 since the maximum is 2.