A sound wave with a frequency of 400 Hz is moving through a solid object. If the wavelength of the sound wave is 8 m, what is th
1 answer:
Answer:
Explanation:
The velocity (speed) of a sound wave (any wave in fact) is related to its frequency and wavelength by the equation . This is easy to remember since it's a distance divided by a time because frequency is the inverse of the period.
Since for sound traveling through the given solid object we have that and
, the speed of sound will be:
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Answer:
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.
Answer:
Explanation:
Let's rewrite F in terms of N.
C is a constant value.
We know that the chemical potential μ is the partial derivative of F with respect to N.
We can find now the chemical potential μ(Vf).
- k is the Boltzmann constant
- N=20 moles
- T is temperature 300 K
- Vi initial volume 0.01 m3
- Vf final volume 0.02 m3
We can do the same to find μ(Vi).
Therefore µ(Vf) - µ(Vi) will be:
I hope it helps you!