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Tema [17]
3 years ago
14

A man on the moon throws a ball vertically upwards and it is noticed that the ball travels 3.0m less in the fifth second of its

upward motion than it does in the third second. What is the acceleration due to gravity on the moon?
Physics
1 answer:
sdas [7]3 years ago
8 0
<h2>Acceleration due to gravity in moon is 1.5 m/s²</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

Here the ball travels 3 m less distance in fifth second compared to third second.

That is

           s₃ = s₅ + 3

Now we have

Distance traveled in third second, s₃ = u x 3 - 0.5 x g x 3² -  u x 2 - 0.5 x g x 2²

           s₃ = u - 2.5 g

Also

Distance traveled in fifth second, s₅ = u x 5 - 0.5 x g x 5² -  u x 4 - 0.5 x g x 4²

           s₅ = u - 4.5 g    

That is

           u - 2.5 g = u - 4.5 g + 3

             2 g = 3

                g = 1.5 m/s²

Acceleration due to gravity in moon = 1.5 m/s²

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Which data set has the largest range?
MrRissso [65]

Answer:

Option C

Explanation:

We have to check range of all options first

For A:

Largest Value: 5

Smallest Value: 1

So range = Largest value - smallest value

5-1 = 4

For B:

Largest Value: 6

Smallest Value: 4

Range = 6-4 = 2

For C:

Largest Value: 9

Smallest Value: 1

Range = 9-1 = 8

For D:

Largest Value = 9

Smallest Value = 3

Range = 9-3=6

So, the data set in option C has the largest range

4 0
3 years ago
Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of
Anastasy [175]

Answer:

<em>d. 268 s</em>

Explanation:

<u>Constant Speed Motion</u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\displaystyle t=\frac{d}{v}

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

\displaystyle t=\frac{5}{67}

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

8 0
3 years ago
How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?
sdas [7]
The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
W=q \Delta V
where q is the charge and \Delta V is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is \Delta V = 9.0 V, so we can find the charge transferred by the battery:
q= \frac{W}{\Delta V}= \frac{39 J}{9.0 V}=4.33 C
3 0
3 years ago
Compare the properties of Titan’s atmosphere with those of Earth’s atmosphere.
Aloiza [94]

Answer and Explanation:

Comparison between the Titan's atmosphere and earth atmosphere

  • Titan atmosphere is more denser than the earth atmosphere
  • The quantity of nitrogen is more in titan atmosphere than earth atmosphere titan atmosphere have about 98 % of nitrogen in the other hand earth atmosphere has only 78 %
  • There are no oxygen present in titan atmosphere while in earth atmosphere it is present
  • Its air is not suitable for breath but in earth atmosphere we can breath
5 0
3 years ago
The temperature of a gas is increased by 10degree Celsius. what is the corresponding change on Fahrenheit scale?​
Grace [21]

On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.

8 0
3 years ago
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