Refraction occurs when a wave changes______ as it passes through a different medium.

Jonny is pushing a 50-kg large package along the dorm room floor with 150 N force. Both the direction of push and the floor are

eduard

a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. The package moves 1.8 m

d. The package's acceleration is 0 m/s²

<h3>a. The horizontal forces</h3>

The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a

Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.

Also, a frictional force also acts to oppose the motion of the package.

Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.

Let

F = push force and
f = frictional force

So, F - f = 0

F = f

= 150 N

So, the frictional force is 150 N and opposite to the push.

So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

<h3>b Vertical forces on package</h3>

The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.

The direction of the weight is downwards while the direction of the normal force is upwards.

Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.

Let W = weight of package = mg where
m = mass of package = 50 kg and
g = acceleration due to gravity = 9.8 m/s² and
N = normal force

So, the net force N - W = 0

N = W

= mg

= 50 kg × 9.8 m/s²

= 490 N

So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

<h3>c. Distance package moves</h3>

The package moves 1.8 m

Since distance, d = vt where

v = velocity = 0.6 m/s and
t = time = 3 s

So, d = vt

= 0.6 m/s × 3 s

= 1.8 m

So, the package moves 1.8 m

<h3>d. The package's acceleration</h3>

The package's acceleration is 0 m/s²

Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where

m = mass of package and
a = acceleration of package

Since F = 0,

ma = 0

a = 0

So, the package's acceleration is 0 m/s²

Learn more about force here:

brainly.com/question/25239010

6 0

3 years ago

A. t = 5.0 min and t = 10.0 min ? m

tensa zangetsu [6.8K]

Answer:

answer b: t=10.0min and t=15.0 m/min is correct

3 0

1 year ago

Three. Grams of the same substance in different phases are stored in three different containers. Each container is barely large

zzz [600]

Complete question is;

Three grams of the same substance in different phases are stored in three different containers. Each container is barely large enough to hold the substance. Which statement can be known about the behavior of the atoms in each container?

A) The atoms in the solid would be moving vigorously around the container.

B) The atoms in the liquid would be vibrating in position.

C) The atoms in the solid would be vibrating in position.

D) The atoms in the gas would be moving slowly around the container.

Answer:

Option C - The atoms in the solid would be vibrating in position

Explanation:

Option A is wrong because the molecules in solids are held together by strong inter molecular forces and therefore can't move about freely but instead will vibrate in their position.

Option B is wrong because the atoms in liquid are more free than those in solids. Thus they will not have room to vibrate.

Option C is correct from the explanation from option A.

Option D is wrong because the atom of the gas would be very loose and free and would therefore be moving very fast around the container

5 0

3 years ago

The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average,

3241004551 [841]

Answer:

For Pentium 4 Prescott:

% of Static Power = 10

For core i5 Ivy Bridge:

% of Static Power = 43

Given Information:

Static Power of P4 = 10 W

Dynamic Power of P4 = 90 W

Static Power of i5 = 30 W

Dynamic Power of i5 = 40 W

Required Information:

% of static power w.r.t total power dissipation = ?

Explanation:

For Pentium 4 Prescott:

% of static power = static power/total power * 100

% of static power = 10/(10 + 90) * 100

% of static power = 10/(100) * 100

% of static power = 10

For core i5 Ivy Bridge:

% of static power = static power/total power * 100

% of static power = 30/(30 + 40) * 100

% of static power = 30/(70) * 100

% of static power = 43 (rounded to nearest whole integer)

5 0

4 years ago

A small wooden block with mass 0.750 kg is suspended from the lower end of a light cord that is 1.72 m long. The block is initia

Ierofanga [76]

Answer:

$v_{0}=319.2 m/s$

Explanation:

We need to use the momentum and energy conservation.

$p_{0}}=p_{f}$

$mv_{0}=(m+M)V_{1}$

Where:

m is the mass of bullet (m=0.01 kg)
M is the mass of the wooden (M=0.75 kg)
v(0) initial velocity of bullet
V(1) is the velocity of the combined object in the moment the bullet hist the block

Conservation of energy.

We have kinetic energy at first and kinetic and potential energy at the end.

$(1/2)(m+M)V_{1}^{2}=(1/2)(m+M)V_{2}^{2}+(m+M)gh$