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3 years ago

Write the equation of the line that passes through the given points. (0,4) and (5,10)

Mathematics

1 answer:

Lunna [17]3 years ago

5 0

Answer: y = 6/5x + 4

Step-by-step explanation: The equation is in form y = mx + b, where m is the slope and b is the y-intercept. You already have the y-intercept, which is 4. To find the slope, use rise over run. y2 - y1 / x2 - x1 = 10-4/5-0 = 6/5.

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What needs to be corrected in this construction of a line parallel to AB passing through Csecond arc (centered at E)

satela [25.4K]

Answer:

Step-by-step explanation:

Report by Oopsydaisy 17.06.2016

Answer

Verified by Expert

Answered by

jamuuj

jd3sp4o0y

+41

jd3sp4o0y and 41 more users found this answer helpful

Answer;

C) The second arc should be centered at C.

Assuming the goal is to construct a line parallel to AB that passes through given point C.

-Draw a line through C and across AB at an angle creating D.

- With the compass width about half of DC, and center D, draw the first arc to cross b

4 0

3 years ago

Please answer <33 I would lava it :)

allsm [11]

Answer:

5 gallons

Step-by-step explanation:

3/4 + 6/8 + 20/8 + 1

6/8 + 6/8 + 20/8 + 8/8

40/8 = 5 gallons

3 0

3 years ago

I need help with percent and tax

sasho [114]

Hello there

56•25/100=

1400÷100=

14$

56-14=42$

He will pay 42$

6 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

What is the square root of 67

Inessa [10]

Every positive number has two square roots.

The square roots of 67 are 8.185... (rounded) and -8.185... (rounded) .

Both are irrational numbers, so they can't be completely written down
with digits. No matter how many decimal places I write, it can never be
enough, because these decimals go on forever and never end.

3 0

3 years ago

Read 2 more answers