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ch4aika [34]
3 years ago
13

Write the equation of the line that passes through the given points. (0,4) and (5,10)

Mathematics
1 answer:
Lunna [17]3 years ago
5 0

Answer: y = 6/5x + 4

Step-by-step explanation: The equation is in form y = mx + b, where m is the slope and b is the y-intercept. You already have the y-intercept, which is 4. To find the slope, use rise over run. y2 - y1 / x2 - x1 = 10-4/5-0 = 6/5.

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What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
Find the slope of the line through the given points (9,2) and (7,8)
Kipish [7]
The velocity, slope, of a line is always (y2-y1)/(x2-x1), in this case:

slope=(8-2)/(7-9)=6/-2=-3

m=-3
3 0
3 years ago
A fabric store sells close-out fabrics for $2.14 a yard. A customer buys 8 yards of fabric. How much does the customer pay for t
blsea [12.9K]

Answer:

$17.12

Step-by-step explanation:

2.14 · 8 = 17.12

8 0
2 years ago
How do I solve this problem?
Ainat [17]
O to f will be 54-59
6 0
2 years ago
Read 2 more answers
Sandra knows the Pythagorean identity sin 2 ⁡ θ + cos 2 ⁡ θ = 1 . If she is told that 0 ≤ θ ≤ π 2 and cos ⁡ θ = 5 12, what will
slavikrds [6]

Answer:

\text{tan}(\theta)=\frac{\sqrt{119}}{5}

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity \text{sin}^2(\theta)+\text{cos}^2(\theta)=1. She is told that 0\leq \theta\leq \frac{\pi}{2} and \text{cos}(\theta)=\frac{5}{12}.

First of all, we will find value of sine theta using the given identity.

\text{sin}^2(\theta)+\text{cos}^2(\theta)=1

\text{sin}^2(\theta)+(\frac{5}{12})^2=1

\text{sin}^2(\theta)+\frac{25}{144}=1

\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}

\text{sin}^2(\theta)=\frac{144-25}{144}

\text{sin}^2(\theta)=\frac{119}{144}

\text{sin}(\theta)=\sqrt{\frac{119}{144}}

\text{sin}(\theta)=\frac{\sqrt{119}}{12}  

\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}

\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}

\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}

Therefore, \text{tan}(\theta)=\frac{\sqrt{119}}{5}.

5 0
3 years ago
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