Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
<span>In 4 years, you will have $324.73</span>
Any
in this set will be real numbers that are both less than
and greater than
. But that's not possible, so this set is empty.
0=0
Step-by-step explanation:
4(×+3)=4x+12
4x+12=4x+12
Subtract 12 from both sides of the equation
4x+12-12=4x+12-12
simplify
4x=4x
Subtract 4x from both sides of the equation
4x-4x= 4x-4x
Simplify and combine like terms
0=0
(50 x 2) + (40 x 2) = 180 yards x 3 = 540 feet of fence needed. 540 / 5 = 108. He will need 108 pieces of fencing
