When the direction is reversed velocity = 0
v = ds/dt = 6t^2 - 42t + 60 = 0
t^2 - 7t + 10 = 0
(t - 5)(t - 2) = 0
t = 2 s and 5 s which are the times when the direction is reversed
Position at t = 2 = 2(2)^3 - 21(2)^2 +60(2) + 3 = 55 feet
at t = 5 position = 28 feet
Acceleration = dv/dt = 12t - 42
At t = 2 acceleration = -18 ft s-2
At t = 5 ............... = 18 ft s-2
If your teacher is asking "which of the following can be used to prove the triangles congruent?" then I agree with your statement that it's "none of the above". We simply don't have enough information to determine if the triangles are congruent or not. If we wanted to use SAS, then we'd have to know if EB = BD was true. If we wanted ASA, then we'd have to know that A = C. If we wanted AAS, then we'd have to know that E = D.
In short, you have the correct answer. Nice work.
Answer:
Translation is moving an object to one place to another.
Step-by-step explanation:
Answer:
x=2 y=-5
Step-by-step explanation:
7x-y=19
2x-3y=19
Multiply the first equation by -3
-3(7x-y)=19*-3
-21x +3y =-57
Add this to the second equation to eliminate y
-21x +3y =-57
2x-3y=19
-----------------------
-19x = -38
Divide by -19
-19x/-19 = -38/-19
x = 2
Now we need to find y
7x-y = 19
7(2) -y =19
14 -y =19
Subtract 14 from each side
14-14 -y=19-14
-y=5
Multiply by -1
y = -5
You can substitute in values of x into the given equation y = 4x^2 - 1 and determine their corresponding y values. Then see which of these points correspond to the graphs q, r, s, t.
For example, if x = 0, then
y = 4(0)^2 - 1
y = -1
The point would be (0, -1)
If x = 1, then
y = 4(1)^2 - 1
y = 4 - 1
y = 3
The point would be (1, 3)
The only graph with points (0, -1) and (1, 3) is graph t.
