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3 years ago

How many minutes are in 2/4 if an hour

2 answers:

8 0

2/4 of an hour simplifies to 1/2 an hour, and because there are 60 minutes in an hour, 60 divided by 2 is 30, meaning there is 30 minutes in 2/4 of an hour.

Katyanochek1 [597]3 years ago

5 0

2/4 of an hour is half an hour so 2/4 of an hour is 30 minutes. Hope it helps

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Kiera used place value and the distributive property to find the product of 12 and 597. Her work is shown below. 12(597) = 12(50

olya-2409 [2.1K]

Answer:

(90)(7) ⇒ the error was multiplying 90 and 7.

Step-by-step explanation:

12(597) = 12(500 + 90 + 7)

= 12(500) + (90)(7)

= 6000 + 630

= 6,630

The part in bold shows where the error is. It was not correct to multiply 90 and 7.

The process was to proceed as follows:

12(597) = 12(500 + 90 + 7)

= 12(500) + 12(90) + 12(7)

= 6000 + 1080 + 84

= 7,164

8 0

3 years ago

I don't like word problems, i need help with this guys

alina1380 [7]

Okay so first we want to find out how many cans one person uses a year. To find this we divide 16,801 by 53 and we get 317 cans a year. Using this we can find how many cans 1,694,000 people use a year by multiplying the people by 317. You get 536,998,000 cans a year, which is your answer.

7 0

3 years ago

Solve the problem using the guess-and-check method.

ehidna [41]

Answer is 14 lightbulbs

8 0

3 years ago

How much are 10 australian dollars worth in Canadian dollars

cupoosta [38]

Answer: 8.94

Step-by-step explanation:

6 0

3 years ago

SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council

fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = $\frac{x-1100}{200}$

$P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517$

4 0

3 years ago