Answer:
• David
,
• 4 miles
Explanation:
In the graph:
The given locations are:
• Owen's House, A(11,3)
,
• David's House, B(15,13)
,
• School, C(3,18)
We determine both Owen's and David's distance from the school using the distance formula.
![Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Owen's distance from school (AC)
![\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AC%3D%5Csqrt%5B%5D%7B%283-11%29%5E2%2B%2818-3%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%28-8%29%5E2%2B%2815%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B64%2B225%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B289%7D%20%5C%5C%20AC%3D17%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
David's distance from school (BC)
![\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20BC%3D%5Csqrt%5B%5D%7B%283-15%29%5E2%2B%2818-13%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%28-12%29%5E2%2B%285%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B144%2B25%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B169%7D%20%5C%5C%20BC%3D13%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
We see from the calculations that David lives closer to the school, and by 4 miles.
The graph below is attached for further understanding:
Answer: 336.80 miles,
North of east
Step-by-step explanation:
Given
Plane lands at a point 324 miles east and 92 miles north
Distance is given by using Pythagoras theorem
![\Rightarrow d=\sqrt{324^2+92^2}\\\\\Rightarrow d=\sqrt{113,440}\\\\\Rightarrow d=336.80\ \text{miles}](https://tex.z-dn.net/?f=%5CRightarrow%20d%3D%5Csqrt%7B324%5E2%2B92%5E2%7D%5C%5C%5C%5C%5CRightarrow%20d%3D%5Csqrt%7B113%2C440%7D%5C%5C%5C%5C%5CRightarrow%20d%3D336.80%5C%20%5Ctext%7Bmiles%7D)
Direction is given by using figure i.e.
![\Rightarrow \tan \theta=\dfrac{92}{324}\\\\\Rightarrow \tan \theta=0.2839\\\\\Rightarrow \theta=15.85^{\circ}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctan%20%5Ctheta%3D%5Cdfrac%7B92%7D%7B324%7D%5C%5C%5C%5C%5CRightarrow%20%5Ctan%20%5Ctheta%3D0.2839%5C%5C%5C%5C%5CRightarrow%20%5Ctheta%3D15.85%5E%7B%5Ccirc%7D)
Direction is
North of east
The average speed for the trip is 11 miles per hour, or mph. 99 miles divided by 9 is 11
A scaled copy with the scale factor being 3/4 it would be smaller because it’s less than one so whenever there is a fraction that’s less than one then the shape would be smaller aswell
Answer:
7.75
Step-by-step explanation:
(I'm assuming you need to find the missing side of the triangle)
To find missing values in a right angle. we will use the pythagoras theorem which states that:
h^2 = a^2 + b^2
16^2 = 14^2 + b^2
256 = 196 + b^2
256 - 196 = b^2
60 = b^2 (take sqaure root)
b= 7.75
Answer from Gauthmath