Two water balloons were launched into the air at different moments and collided. the water balloons were modeled by the quadratic functions: y = −7x2 26x 3 and y = −6x2 23x 5, where y represents the height in meters and x represents the time in seconds after the launch. 2.0 seconds is the time, in seconds, that the balloons collided at the highest point
The time in seconds that the balloons collided at the highest point is; B: 2.0 seconds
We are told that the water balloons were modeled by the quadratic functions:
y = -7x² + 26x + 6 and y = -6x² + 25x + 4
where;
y = the height in meters
x = the time in seconds after the launch
The time at which they will collide has to be at the same height.
Thus;
-7x² + 26x + 6 = -6x² + 25x + 4
Rearranging this gives;
x² - x - 2 = 0.
Using an online quadratic equation solver gives us x = 2 or -1. We will take the positive one as x = 2.0 seconds
Learn more about quadratic equations at
brainly.com/question/1214333
#SPJ4
9514 1404 393
Answer:
- $10,000 at 5%
- $22,000 at 6%
Step-by-step explanation:
Let x represent the amount invested at 6%. Then 32000-x is the amount invested at 5%, and the total interest earned is ...
0.06x +0.05(32000 -x) = 1820
0.01x +1600 = 1820 . . . . simplify
0.01x = 220 . . . . . . . . . . subtract 1600
x = 22,000 . . . . . . . . . . . multiply by 100
32000 -x = 10,000
Phyllis invested $22,000 at 6% and $10,000 at 5%.
Answer:
3
Step-by-step explanation:
4362
3= hundreds place value
So that means there are 3 whole hundreds
Answer:
x=4
Step-by-step explanation:
Given:
First term of an arithmetic sequence is 2.
Sum of first 15 terms = 292.5
To find:
The common difference.
Solution:
We have,
First term: 
Sum of first 15 terms: 
The formula of sum of first n terms of an AP is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where, a is first term and d is common difference.
Putting
, n=15 and a=2 in the above formula, we get
![292.5=\dfrac{15}{2}[2(2)+(15-1)d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B2%282%29%2B%2815-1%29d%5D)
![292.5=\dfrac{15}{2}[4+14d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B4%2B14d%5D)
![292.5=15[2+7d]](https://tex.z-dn.net/?f=292.5%3D15%5B2%2B7d%5D)
Divide both sides by 15.




Dividing both sides by 7, we get


Therefore, the common difference is 2.5.