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RUDIKE [14]
3 years ago
7

Pranked haha hkjkdvhpihigiuaspihgpiaisuhgiuasi free redit

Mathematics
2 answers:
iren2701 [21]3 years ago
6 0
Okay the answer is 69 because 81-2 is 69
olganol [36]3 years ago
5 0
Up vote this one plz I need some coins
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Tom has a fair spinner with six sides.
77julia77 [94]

Answer:

likely ❤️❤️❤️❤️❤️❤️❤️

3 0
3 years ago
The variables x and y have a proportional relationship, and y=5/6 when x=3/4. Which equation represents this relationship?
seropon [69]

Answer:

y = 1 1/9

BRO MAKE ME THE BRAINLIEST PLS

4 0
2 years ago
I am needing to know the answer to 3/7 of what number is 9?
kolezko [41]
In math, "of" almost always means "times".

So your question is:  3/7 times (the number) = 9

Multiply each side of that equation by  7 :   3 times (the number) = 63

Divide each side by 3 :             <em> The number = 21</em>
3 0
3 years ago
Read 2 more answers
Solve for y 16y^2-25=0
Pepsi [2]

Answer:

\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}

METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

7 0
3 years ago
Read 2 more answers
Find the prime factorization for the number m (if possible) that makes each of the following true. If no number is possible, exp
SSSSS [86.1K]

Answer:

Is not possible to find a prime factorization for m.

Step-by-step explanation:

if

2^3 . 19^5 . 23^4 = 2^3 . 19^5 . 46 . m

then

m=\frac{2^3. 19^5 . 23^4}{2^3 . 19^5 . 46 }=\frac{2^3. 19^5 . 23^4}{2^3 . 19^5 . 2.23 }=\frac{23^3}{2}

So m is not an integer, hence it cannot be decomposed in prime factors.

3 0
3 years ago
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