Answer:
yes
Step-by-step explanation:
Answer:
Standard error (S.E) = 0.048 ≅ 0.05
Step-by-step explanation:
<u>Explanation</u>:-
Given sample size 'n'=76
Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.
Sample proportion
![p = \frac{x}{n} = \frac{58}{76} = 0.7631](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cfrac%7B58%7D%7B76%7D%20%3D%200.7631)
The standard error is determined by
![S.E = \sqrt{\frac{p(1-p)}{n} }](https://tex.z-dn.net/?f=S.E%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D)
Standard error is 0.048 ≅ 0.05
Answer:
has to be B or C
Step-by-step explanation:
i had the same question
do u do flvs???
I think the answer is ;B.316 and 38