3 years ago

Please help me find y

Mathematics

1 answer:

sertanlavr [38]3 years ago

3 0

Answer:

Step-by-step explanation:

cos 60° = y / 10

y = 10 * 1/2 = 5

You might be interested in

Please answer if you can 30 points.

Rudik [331]

Answer:

The y-intercept is 4

Step-by-step explanation:

You find the y-intercept by finding where x is zero. In the table, when x=0 the y=4. The y-intercept is 4. The graph of the function crosses the x-axis at the point (0,4).

4 0

2 years ago

Read 2 more answers

PLZZZZZZ HELP IM GIVING 20 BRAINLY

SpyIntel [72]

Answer:

4/5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I participated in a math competition but I did not do very good. Does anybody have some tips?

Stells [14]

Study 5 times on the subject you are focusing on.

4 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

More help please lol

amm1812

Answer:

46.03 = 46.030

Step-by-step explanation:

they are the same nub,er except they put another zero at the end of the one on the right

4 0

3 years ago

Read 2 more answers