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zheka24 [161]
3 years ago
9

* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both

sequence A and sequence B. Is Sally right? You must explain your answer.
Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective n^{th} terms as following:

Sequence A. 3n - 2

Sequence B. 10 - 2n

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the n^{th} terms of the respective sequences as equal and let us verify that.

3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}

When we talk about n^{th} terms, n here is a whole number not a fractional number.

But as per the statement as stated by Sally n is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

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defon

Given the System of Equations:

\begin{cases}y=4x-1 \\  \\ y=x-4\end{cases}

The exercise asks for solving it graphically. Then, in this case, you need to graph both lines in order to determine the solution of the system.

In order to graph it, you can find the x-intercepts and the y-intercepts:

1. It is important to remember the Slope-Intercept Form of the equation of a line:

y=mx+b

Where "m" is the slope of the line and "b" is the intercept.

In this case, you can identify that the y-intercept of the first line is:

b_1=-1

And the y-intercept of the second line is:

b=-4

2. By definition, the value of "y" is zero when the line intersects the x-axis.

Then, you need to substitute the following value of "y" into each equation and then solve for "x", in order to find the x-intercept of each line:

y=0

- For the first line, you get:

\begin{gathered} y=4x-1 \\ 0=4x-1 \\ 1=4x \\  \\ \frac{1}{4}=x \\  \\ x_1=0.25 \end{gathered}

- For the second line, you get:

\begin{gathered} y=x-4 \\ 0=x-4 \\ 4=x \\ x_2=4 \end{gathered}

3. Now you know that the first line passes through these two points:

(0.25,0);(0,-1)

And the second line passes through these two points:

(4,0);(0,-4)

4. Knowing those points, you can graph the lines:

Notice that the line intersect each other at

5 0
1 year ago
What is the greatest three-digit multiple of 33 that can be written using three different digits?
tatuchka [14]

Answer:

I don't if this is right but is the 629

Step-by-step explanation:

8 0
3 years ago
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konstantin123 [22]

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8 0
3 years ago
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aleksley [76]

Answer:

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8 0
3 years ago
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I need help n pls explain ​
WARRIOR [948]

Answer:

The correct option is C). When it was purchased, the coin was worth $6

Step-by-step explanation:

Given function is f(t)=6\times2^{t}

Where t is number of years and f(t) is function showing the value of a rare coin.

A figure of f(t) shows that the graph has time t on the x-axis and f(t) on the y-axis.

Also y-intercept at (0,6)

hence, when time t was zero, the value of a rare coin is 6$

f(t)=6\times2^{t}

f(0)=6\times2^{0}

<em>f(0)=6</em>

Thus,

The correct option is C). When it was purchased, the coin was worth $6

6 0
3 years ago
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