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3 years ago

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Em um posto de combustível, o litro da gasolina estava custando R$2,40.Um cliente gastou R$72,00 para encher o tanque de seu car

ro. O valor do litro da gasolina sofreu 2 aumentos sucessivos,ambos de 10%. Quando o mesmo cliente gastara para encher o tanque do seu carro, após esees aumentos

1 answer:

Julli [10]3 years ago

7 0

Answer:

english i think u need hekp

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Students at sunnyvale Middle School volunteered to work a 2-hour Shift at a car wash fundraiser. The table shows the number of p

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the number of cars washed per person is not the same for each number of workers, so the relationship is not proportionalStep-by-step explanation:

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3 years ago

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Translate to an algebraic expression.

beks73 [17]

The answer is d=63/z

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3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

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2 years ago

Please Help! I’m to lazy to do it my self TwT

zvonat [6]

Answer:

Step-by-step explanation:

multiples of 5 are 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100

multiples of 4 are 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 64 68 72 76 80

the least common multiple they have is 20 mark brainliest thanks

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3 years ago

19 dollars for 5 books

viktelen [127]

Answer:

$3.80 per book

Step-by-step explanation:

I divided 19 by 5 to get the price per book

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3 years ago