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anyanavicka [17]
1 year ago
14

Math!! please please helppp!!!

Mathematics
2 answers:
Elodia [21]1 year ago
5 0

Answer:

3

Step-by-step explanation:

Look at the two lower dots shown on the line.

slope = rise/run

The vertical distance from the lower point to the higher point is 3. That is the rise.

The horizontal distance from the lower point to the higher point is 1. That is the run.

slope = 3/1 = 3

Answer: 3

Margarita [4]1 year ago
3 0

Answer:

The slope is 3

Step-by-step explanation:

it is 3 up and 1 across, which is 3/1 = 3

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When 15 minus 3 is multiplied by a number the product is 2.
AlexFokin [52]
The number is 1/6. 15 minus 3 = 12. 12 times 1/6 is 2
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2 years ago
Please help with the picture below
elena-s [515]

Answer:

Step-by-step explanation:

Remark

The angles are marked as alternate interior angles. To be parallel, they must be equal. In other words x - 20  must equal 52. That's all you have to do. Just equate the 2 givens and solve.

Givens

x - 20 is one angle

52 is the other.

Solution

x - 20 = 52                   Add 20 to both sides.

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Answer: C

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2 years ago
PLEASE HELP ME WITH BOTH MATH QUESTIONS ASAP!!!!!!!!!
maxonik [38]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
Please Help!!! I've been stuck on this question for the longest and none of the answer choices are the answer I keep on getting.
Vera_Pavlovna [14]

I think the answer might be <em>B 30.4 ft</em> if it not it might be <em>C 161 ft</em>

pls correct me if i'm wrong sorry if the answers is wrong

5 0
3 years ago
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