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Nutka1998 [239]
3 years ago
11

Find the surface area

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0
I got 73.7460555 not rounded 
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Please can someone help me answer these questions? Would be really grateful if it was done by the 12th of January. Thank you :)
FrozenT [24]
1. 4g= 37-5
 ⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8

2. c= 5*6
⇒ c= 30

3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.

4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0

5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17

6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7

7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9

8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8

9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0

10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24

11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3

12. x/3= 6-7
⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3

13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2

14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8

15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5

16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3

17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
⇒ v= 1.2

18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
⇒ n= 21

19. t+10= 1*4
⇒ t+10= 4
⇒ t= 4-10
⇒ t= -6

20. 3c+4= 3*5
⇒ 3c+4= 15
⇒ 3c= 15-4
⇒ 3c= 11
⇒ c= 11/3
⇒ c= 3 2/3

Hope this helps~
6 0
3 years ago
Read 2 more answers
In the triangle below, with right angle , suppose that and .
bazaltina [42]

Answer:

G= 60.5

E= 70.9

F= 90

........

.......

4 0
2 years ago
The area of a mirror is 225 square inches, and its width is 13 3/4 inches. Will the mirror fit in a space that is 15 inches by 1
gavmur [86]
If you multiply length times width to get area, it's the same with division. You do area divided by length or width. The equation would be 225 divided by 13 3/4. 225/13 3/4= 16.36 inches. 16.36 > 16 inches, so the answer would be no. (The mirrors length and width are 13 3/4 inches by 16 9/25)
7 0
3 years ago
A meat pie contains chicken and turkey in the ratio 4: 1. The pie contains 200g of chicken.
tatyana61 [14]

How much turkey is in the pie?

The mass of the turkey in the pie is 1/4 of the weight of the chicken

200/4 = 50 grams

5 0
2 years ago
Which of the following angles is in the solution set of sec^2θ - 3secθ - 2 = 0 for 0° ≤ θ < 360°.
STALIN [3.7K]
1 / cos^2 O - 3 / cos O - 2 = 0
1 - 3 cos O -  2 cos^2 O = 0

2 cos^2 O + 3 cos O - 1 = 0

cos O = 0.2807 , -1.78   ( -1.78 cannot be a solution)

O = 74 degrees  (from  0.2807) another solution is 360-74 =  286 degrees

Its D
4 0
3 years ago
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