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laiz [17]
3 years ago
13

What is the additive inverse of 1?​

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

Answer:

multiplicative inverse 1 is 1

Step-by-step explanation:

(happy to help!!!)

brilliants [131]3 years ago
5 0

Answer:

the additive inverse of 1 is 1 because 1+1=0 and the multiplicative inverse of 1 is 1.

Step-by-step explanation:

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Point D is on segment BC, Segment BC measures Bx
Nostrana [21]

Answer:

144 units

Step-by-step explanation:

3x + 8 + 4x + 10 = 8x

7x + 18 = 8x

8x - 7x = 18

x = 18

8x is length of BC

8 × 18 is length of BC

144 units

5 0
3 years ago
In all, 1000 students took a statistics exam worth 150 points. The first quartile (or Q1) for all 1000 scores is 90 points. Abou
Brums [2.3K]

Answer:

The number of students who scored more than 90 points is 750.

Step-by-step explanation:

Quartiles are statistical measures that the divide the data into four groups.

The first quartile (Q₁) indicates that 25% of the observation are less than or equal to Q₁.

The second quartile (Q₂) indicates that 50% of the observation are less than or equal to Q₂.

The third quartile (Q₃) indicates that 75% of the observation are less than or equal to Q₃.

It is provided that the first quartile is at 90 points.

That is, P (X ≤ 90) = 0.25.

The probability that a student scores more than 90 points is:

P (X > 90) = 1 - P (X ≤ 90)

                = 1 - 0.25

                = 0.75

The number of students who scored more than 90 points is: 1000 × 0.75 = 750.

4 0
3 years ago
Read 2 more answers
1
Arlecino [84]

Answer: B.), D.), and E.)

Step-by-step explanation:

That’s the answer on USAtestprep

3 0
3 years ago
X^8+8x^7+15x^6−9x^5−72x^4−135x^3+8x^2+64x+120
LenaWriter [7]

Answer:

(x+3)(x+5)<em>(x-2)(x-1)</em><u>(x^2+2x+4)(x^2+x+1)</u> where the given one is bolded the 2 binomials is italicized  and the 2 trinomials is underlined

Step-by-step explanation:

6 0
3 years ago
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
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