Answer:
The partial quotients are 100, 20 and 6. The quotient is 126.
Step-by-step explanation:
The dividend is 378 and the divisor is 3.
First find the factors of 3, near to 300.
The value 300 is less than 378, so record the partial quotient 100 and subtract 300 from 378. Repeat the same process until the dividend has been zero.
Now the remaining divide is 78.
First find the factors of 3, near to 78.
Since 90>78, therefore 30 is not a partial quotient. The value 60 is less than 78 , so record the partial quotient 20 and subtract 60 from 78.
Now the remaining divide is 18.
The number 6 is a partial quotient.
Therefore partial quotients are 100, 20 and 6. Add the partial quotient to find quotient.
Equation = y = mx + b
y = 3/4x + b
Calculation for b.,
-5 = 3/4 * 4 + b
b = -5/3
So, your final answer is y = 3/4x - 5/3
Hope this helps!
Answer:
120
Step-by-step explanation:
Im not sure but 1.25 equals 1 1/4 and 16 cups equal a gallon.
16 divided by 1.25 is 12 which means that 12 of those ten servings equal a gallon. 10 times 12 is 120 which becomes ur answer. Once again im not sure but i hope that ive helped.
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
B. If Karl runs 1 mi, then he runs 5280 ft.
If A then B and if B then C, then A-->C
