<span>Center(0,0)
a^2=16
a=4
b^2=9
b=3
c^2=a^2+b^2=16+9=25
c=√25=5</span>
The hypotenuse can be solved by this formula. X^2 = 6^2 +6^2
X^2=64
Usually you cut it down to 8 but it wants the squared form so 64.
Answer:
8jbggvvhj was born on a 5
Answer:
See below
Step-by-step explanation:
Your question is a bit unclear, so I'm going to assume you want the value of y or x:
(y+3)^2=-12(x-2)
-(y+3)^2/12=x-2
-(y+3)^2/12+2=x
(y+3)^2=-12(x-2)
y+3=sqrt(-12x+24)
y=sqrt(-12x+24)-3
