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Andre45 [30]
3 years ago
15

The band boosters collected $2400 from the sale of hamburgers and hotdogs.The amount earned from hamburgers and hotdogs were equ

al.A hamburger sold for three dollars and a hotdog sold for two dollars how many of each were sold?
Mathematics
2 answers:
adell [148]3 years ago
5 0
6,000 for the hotdogs and 4,000 for the hamburgers
damaskus [11]3 years ago
4 0
400 Hamburgers
600 Hot dogs

Divide 2,400 by two because that's how many items they sold. You'll get 1,200.

Divide 1,200 by 3 because that's how much a hamburger costs and you'll end up with 400

Divide 1,200 by 2 because that's how much a hot dog costs and you'l end up with 600

To check, multiply 400x3 and 600x2

Then add the sums together- 1,200+1,200= 2,400
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Find the ratio of x to y is 5y=3x
Colt1911 [192]

Answer:

\frac{x}{y} = \frac{5}{3}

Step-by-step explanation:

given 5y = 3x ( divide both sides by 3 )

\frac{5}{3} y = x ( divide both sides by y )

\frac{5}{3} = \frac{x}{y}




5 0
3 years ago
Read 2 more answers
Let f(x) = 5x2 – 4x and g(x) = 5x + 1.
Nastasia [14]

f(x) = 5x^2 - 4x

g(x) = 5x + 1

Therefore f - g = 5x^2 - 4x - (5x + 1)

= 5x^2 - 4x - 5x -1

= 5x^2 -9x - 1


Hope it helps :)











8 0
3 years ago
Read 2 more answers
Ethan has $620 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax. He buys a
garri49 [273]

Answer: 620≥ 427.57+ 11.38(4)+ (31.41) +57.75x

Step-by-step explanation:

So our limit is the 620$ that he has to spend. We know for a fact that the bike costs about 427.57 dollars. 4  $11.38 reflectors are purchased as well as gloves for 31.41.  Now however many outfits he can purchase cannot exceed or go over his money limit of 620 so the variable (x) represents how many outfits he can buy without going over.

6 0
3 years ago
If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure
const2013 [10]

Answer:

DG = 26

GE = 26

DF = 15

CH = 14

CE = 28

Step-by-step explanation:

The figure has been attached, to complement the question.

DE = 52

FC = 15

HE = 14

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

DF = FC

CH = HE

DG = GE

Solving (a): DG

If DG = GE, then

DE = DG + GE

DE = DG + DG

DE = 2DG

Make DG the subject

DG = \frac{1}{2}DE

Substitute 52 for DE

DG = \frac{1}{2} * 52

DG = 26

Solving (b): GE

If DG = GE, then

GE = DG

GE = 26

Solving (c): DF

DF = FC

So:

DF = 15

Solving (d): CH

CH = HE

CH = 14

Solving (e): CE

If CH = HE, then

CE = CH + HE

CE = 14 + 14

CE = 28

7 0
3 years ago
PLZ HELP! Work must be shown for this problem. Solve for x. Round answers to the nearest hundredth (2 decimal places).
Leviafan [203]

Answer:

About 555.43 feet

Step-by-step explanation:

The sine of an angle is equivalent to the length of the opposite side divided by the length of the hypotenuse. In this case:

\sin 80= \dfrac{x}{564} \\\\x=\sin 80 \cdot 564\approx 555.43

Hope this helps!

3 0
4 years ago
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