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Grace [21]
2 years ago
15

If MNOP is an isosceles trapezoid MP=16x-13, NO=9x+8, MO=12y-7 solve for x and y

Mathematics
2 answers:
Darina [25.2K]2 years ago
8 0
X equals 3 and y equals .58
allochka39001 [22]2 years ago
7 0
X equals 3 and y equals. 58
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Graph the points and state whether they are collinear.
Alchen [17]
All that is needed is for you to graph the points and if they form a line, they will be collinear. If not, they will not be collinear.
4 0
3 years ago
C=59(F−32)
neonofarm [45]
I says every time you INCREASE by 1 degree Farenheit you go up 59 degrees C, so it is false. Same for III, if you go up or down 1 degree C that's not a change of 59 in degrees F.

That leaves B, which is right if you experiment with the math.
8 0
3 years ago
Help me plz and ty....​
nadya68 [22]

Answer: c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the value of x? Enter your answer in the box.
mario62 [17]
X = 12

because if you notice, each of the angles have a little arc in the corner, which means they are congruent. if all three angles are congruent, that means each angle is 60° because each triangle has a maximum value of 180°. therefore, this means it is an equilateral triangle.

that being said, each side must be equal as well. so, you can use any two sides to find x by using each one on a different side of an equation, then isolating and solving.

5x - 22 = 3x + 2 = 4x - 10

so

5x - 22 = 3x + 2
3x + 2 = 4x - 10
4x - 10 = 5x - 22

whichever one you solve for, x = 12. and if you plug in that number for x, each side equals the same number = 38
8 0
3 years ago
Which function has the same y-intercept as the one below
Over [174]

Check the picture below, so let's check the equations below hmmm

\boxed{A}\\\\ y=\cfrac{16-3x}{4}\implies y=\cfrac{-3x+16}{4}\implies y = \cfrac{-3x}{4}+\cfrac{16}{4}\implies y=-\cfrac{3}{4}x\stackrel{\stackrel{b}{\downarrow }}{+4}~\hfill \bigotimes \\\\[-0.35em] ~\dotfill

\boxed{D}\\\\ y+4=2x\implies y=2x\underset{\stackrel{\uparrow }{b}}{-4}\qquad \textit{\Large \checkmark}\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

5 0
2 years ago
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