Answer:
x ≈ 8.9
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, the the square of the tangent is equal to the product of the external part of the secant and the entire secant, that is
x² = 8(8 + 2) = 8 × 10 = 80 ( take the square root of both sides )
x = ≈ 8.9 ( to the nearest tenth )
Answer:
W1 = ( -75, 20, 1 , 0 )
W2 = ( 25, -7 , 0, 1 )
Step-by-step explanation:
attached below is the remaining part of the solution
for a homogenous system of equation ; Ax = 0
x1 + 4x2 -5x3 + 3x4 = 0
-x2 + 20x3 -7x4 = 0 note: x3 and x4 are free variables
we can take x3 = 0 and x4 = 1 , hence ; x2 = -7
∴ x1 - 28 + 3 = 0 = x1 = 25
W2 = ( x1 ,x2, x3, x4 ) = ( 25, -7 , 0, 1 )
now lets take x3 = 1 and x4 = 0 hence x2 = 20 , x1 = -75
∴ W1 = ( x1 , x2 , x3, x4 ) = ( -75, 20, 1 , 0 )
