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Brums [2.3K]
3 years ago
15

Need help please on how to find

"latex-formula">

(x*7)^{x}=3^{3}*7^{3}
Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

You're answer would end up being x=1323

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Every month, Jim makes $49 less than his best friend Keenan.
ad-work [718]

Answer:

m+49=d ; d-49 = m

Step-by-step explanation:

Jim $ = m

Keenan $ = d

m+49=d ; d-49=m

btw please lmk if i get this wrong

6 0
2 years ago
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A little help please?
Tasya [4]
3x-10+2x=115
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Evaluate the following expression. [4 + (12 - 2) ÷ 5] ÷ 7
Anika [276]

Answer:

[4 + (12 - 2) ÷ 5] ÷ 7

[4 + 6 / 5] / 7

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Fractions and integer operations practice, I need help please.
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3 years ago
Solve 4 cos2x-3 = 0 for all real values of x.
vichka [17]

4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

3 0
3 years ago
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