What is the measure of the secant CD
1 answer:
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Answer:
The percentage that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = 83.9≅ 84 percentage</em>
Step-by-step explanation:
<u> Step(i):-</u>
Mean of the Population = 8.3 points
Standard deviation of the Population = 0.5 points
Let 'X' be the random variable in normal distribution
<em>Let X = 6.8</em>
Let X = 8.8
The probability that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = P(-3≤Z≤1)</em>
= P(Z≤1)- P(Z≤-3)
= 0.5 + A(1) - ( 0.5 -A(-3))
= A(1) + A(3) (∵A(-3)=A(3)
= 0.3413 +0.4986 (∵ From Normal table)
= 0.8399
<u><em>Conclusion:-</em></u>
The percentage that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = 83.9≅ 84 percentage</em>