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lozanna [386]
4 years ago
14

Consider a mixture of four proteins with various molecular weights. A histone molecule weighs 15 kDa, 15 kDa, a p53 molecule wei

ghs 53 kDa, 53 kDa, an actin molecule weighs 42 kDa, 42 kDa, and an IgG molecule weighs 150 kDa. 150 kDa. Arrange the molecules in order of their elution from a gel filtration column.
Chemistry
1 answer:
IRISSAK [1]4 years ago
3 0

Answer:

  1. IgG
  2. p53
  3. Actin
  4. Histone

Explanation:

In <em>gel filtration chromatography</em> a porous matrix is used as the stationary phase. The smaller molecules are able to diffuse into this matrix while the larger ones are not. For this reason the larger molecules will elute first, followed by the smaller ones in decreasing order of size.

In other words the largest molecule will elute first and the smallest molecule will elute last:

  1. IgG
  2. p53
  3. Actin
  4. Histone

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Jacob carelessly added only 40.0 mL (instead of the recommended 50.0 mL) of 1.1 M HCl to the 50.0 mL of 1.0 M NaOH. Explain the
Sati [7]

Answer:

Explanation:

mole of NaOH present = molarity x volume

                                     = 1.0 X 0.05 = 0.05 mole

<em>Recommended mole of HCl </em>= 1.1 x 0.05 = 0.055

<em>Mole of HCl carelessly added by Jacob </em>= 1.1 x 0.04 = 0.044

From the equation of reaction:

HCl + NaOH ----> NaCl + H2O

The ratio of mole of HCl to that of NaOH for a complete neutralization reaction is 1:1. However, the recommended mole of HCl (0.055 mole) is more than the mole of NaOH (0.05 mole). <u>Hence, the recommended endpoint of the reaction is supposed to be acidic.</u>

The mole of HCl added by Jacob (0.044) is short of the recommended amount (0.055) and also short of the amount required for a neutral endpoint (0.05). <u>This means that the endpoint will have an excess amount of NaOH and as such, basic instead of the desired acidic endpoint.</u>

8 0
3 years ago
If you wanna get oil to 180 celcius when it starts at 20 how many units of thermal energy is needed?
Zarrin [17]

Answer:

The thermal energy (heat) needed, to raise the temperature of oil of mass  'm' kilogram and specific heat capacity 'c' from 20°C to 180°C  is  160·m·c joules

Explanation:

The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT

∴ C = ΔQ/ΔT

ΔQ = C × ΔT

C = m × c

Where;

c = The specific heat capacity

ΔT = The temperature change = T₂ - T₁

∴ ΔQ = m × c × ΔT

Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C  is given as follows;

ΔQ = m × c × (180° - 20°) = 160° × m·c

ΔQ = 160·m·c joules

7 0
3 years ago
If the formation of NaCl proceeds according to the following equation and change in enthalpy, what is the reaction and change in
Sergio039 [100]

Answer:

  • <em>2NaCl → 2Na + Cl₂, ΔH = 822 kJ </em>

Explanation:

The chemical <em>equation</em> for the <em>formation of NaCl</em> is:

  • Na + (1/2) Cl₂ → NaCl , ΔH = - 411 kJ

That equation means that 1 mole of NaCl is formed by the reaction of 1 mole of Na and 1/2 mole of Cl₂, with a release of energy of 411 kJ.

The <em>decomposition</em> of <em>NaCl</em> is the inverse of the <em>formation</em> reaction; thus, you swift products and reactants and inverse the sign of the <em>change in enthalpy:</em>

  • NaCl → Na + 1/2 Cl₂, ΔH = 411 kJ

Since you want the decomposition of 2 moles you multiply the equation and the ΔH by 2:

  • 2NaCl → 2Na + Cl₂, ΔH = 822 kJ ← answer

3 0
3 years ago
What must group 16 do to become stable
tamaranim1 [39]
Group 16 must gain 2 electrons to become stable as stated in my other answer 

Hope this helped

7 0
3 years ago
Read 2 more answers
The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
Norma-Jean [14]
Matter is made of very tiny particles. One mole of a substance contains a given amount of particles. This number is constant for all particles- 6.022×10^23<span> , and is called Avogadro's constant. To get the number of particles in 4g of butane, we need to calculate the number of moles represented by 4 g, then multiply by the Avogadro's constant (Since each mole has particles equivalent to the Avogadro's constant) 
Therefore, if 1 mole = 58.1g
                how many moles will be equal to 4g?
                we cross multiply  (4x1) divide by 58.1
                equals 0.068847moles
multiply by Avogadro constant = 4.1466 x 10^molecules
But remember the question is not about the number of molecules in butane, its about the number of carbon atoms. 
Since there are four carbons in butane, and each has </span> 4.1466 x 10^22 atoms
to get the number of atoms, we multiply by four
equals 1.6586 x 10^atoms

7 0
3 years ago
Read 2 more answers
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