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3 years ago

Solve: 9^2x + 1 = 9^3x – 2

Mathematics

2 answers:

nirvana33 [79]3 years ago

7 0

Answer:

1/216

Step-by-step explanation:

Move variables to one side and constants to the other

9^3x-9^2x=3

factor out 9^2x

(9^2x)(8)=3

9^2x=3/8

3^4x=3/8

3^3x=1/8

x=1/8 x 27

x=1/216

kipiarov [429]3 years ago

6 0

Answer:

x = 1/216

Step-by-step explanation:

Simplify the equation, like the powers.

81x + 1 = 729x - 2

Subtract 729x on both sides to balance the equation.

-648x + 1 = - 2

Then subtract 1 from both sides.

-648x = -3

Finally divide by -648, which then leaves x equal to 1/216

x = 1/216

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3 years ago

Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7

Dima020 [189]

Answer:

The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ .

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

$\dfrac{\textrm factor of P}{\textrm factor Q}$ ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial , P = -7 , Q = 4

Now , $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$

I.e $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$ = $\frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }$

Or, The rational zero are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$

Hence The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ . Answer

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3 years ago

(3ab-3a-8)-(-4ab-8) find the difference

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3 years ago

Please help me!!! What is the value of n? 2n = 8 + 4n A)-4 B) 4 C)-4/3 D)4/3

erica [24]

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Hope this helps

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3 years ago