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dlinn [17]
3 years ago
14

At a local college, 65 female students were randomly selected and it was found that their mean monthly income was $628 with a st

andard deviation of $121.50. Seventy-five male students were also randomly selected and their mean monthly income was found to be $670 with a standard deviation of $168.70. Test the claim that male students have a higher monthly income than female students. Use α = 0.01. Group of answer choices
a. reject H0
b. fail to reject H0
c. not sufficient information to decide
Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

Step-by-step explanation:

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What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
The contagent of 180/3,180/4,180/6 is
just olya [345]

Answer:

easy

Step-by-step explanation:

1+2=92

4 0
3 years ago
Suppose that A = {2,4,6}, B = {2,6}, C = {4,6}, and D = {4, 6, 8}. Determine which of these sets are subsets of which other of t
7nadin3 [17]

Answer:

Sets B and C are subsets of set A

3 0
3 years ago
JRJSOWNDNFNEOSLDNFBWKWLND
abruzzese [7]

Answer:

Step-by-step explanation:

the 1 one is the right one

8 0
3 years ago
Read 2 more answers
Solve for x than find the perimeter
My name is Ann [436]

Answer:

136 in

Step-by-step explanation:

Assuming the figure is a square with equal sides, then

4x - 2 = 3x + 7 ( subtract 3x from both sides )

x - 2 = 7 ( add 2 to both sides )

x = 9

Thus side = 3x + 7 = 3(9) + 7 = 27 + 7 = 34

Thus

perimeter = 4 × 34 = 136 in

8 0
4 years ago
Read 2 more answers
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