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Nesterboy [21]
3 years ago
15

William travels only on Saturdays and Sundays and has flown 400 miles this month. Jason travels every weekday and has flown 500

miles this month. Who travels more miles per day?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0
Let's assume that a month has four weeks.

If William made 400 miles by travelling only on Saturdays and Sundays and there were 4 weekends during the month, then he travels 400 / 4 = 100 miles during a weekend, which is 100 / 2 = 50 miles a day.

If Jason travels every weekday during the month and he does 500 miles, then he travels 500 / 20 = 25 miles a day.

It means that William travels more miles per day.
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P(35.3 < M < 35.4) = 0.0040.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 33.9, \sigma = 6.7, n = 119, s = \frac{6.7}{\sqrt{119}} = 0.6142

Find the probability that a single randomly selected value is between 35.3 and 35.4

This is the pvalue of Z when X = 35.4 subtracted by the pvalue of Z when X = 35.3. So

X = 35.4

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{35.4 - 33.9}{0.6142}

Z = 2.44

Z = 2.44 has a pvalue of 0.9927

X = 35.3

Z = \frac{X - \mu}{s}

Z = \frac{35.3 - 33.9}{0.6142}

Z = 2.28

Z = 2.28 has a pvalue of 0.9887

0.9927 - 0.9887 = 0.0040

So the answer is:

P(35.3 < M < 35.4) = 0.0040.

4 0
3 years ago
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