Question

exFormula1" title=" (8 + 5\sqrt{x} -98) - ( 3 + 6\sqrt{x-32) " alt=" (8 + 5\sqrt{x} -98) - ( 3 + 6\sqrt{x-32) " align="absmiddle" class="latex-formula">

Answer 1

Considering 32 outside the square root .

$(8+5 \sqrt x -98) -(3+6\sqrt x-32)$

Here we have to combine like terms, and like terms are 8 , 98 ,3, 32 and 5 square root x and 6 square root x .

We need to remove the parenthesis and since there is a minus sign outside the second parenthesis , so we have to flip the sign of the terms of second parenthesis. THat is

$8-98-3+32+5 \sqrt x -6 \sqrt x$

=$-61 - \sqrt x$

And that's the final answer .