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oksian1 [2.3K]
3 years ago
11

3. If 4 cards are randomly selected without replacement from a deck of cards, what is the probability of

Mathematics
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

The probability is very high

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Ms. Martinez has a class of 16 students. She can spend $17 on each student to buy math supplies for the year. She first buys all
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Step-by-step explanation:

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A) 363<br><br> B) 33<br><br> C) 7<br><br> D) 77
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2 years ago
X/5 = 2 1/2<br><br> Fraction <br> Have to find x
nadya68 [22]

Answer:

x=12.5

Step-by-step explanation:

x=2 1/2 times 5

x=12.5

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3 years ago
Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
A coin is flipped twice. What is the probability that the coin will land on tails on the first flip and will land on tails again
bixtya [17]

Answer:

1/4=0.25=25%

Step-by-step explanation:

A coin has two sides, heads and tails, and if you take 100% divided by two you get 50, you want to know what is the probability it will land on tails TWICE so divide 50 by two and you get 25.

1/2=50

1/4=25

0.25 x 100= 25%

hope that helps

5 0
2 years ago
Read 2 more answers
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