Question

Find the probability of getting a non prime number if a die is thrown once

Answer 1

Answer:

Probability to get a non prime number is $\frac{1}{3}$

Step-by-step explanation:

When a die is thrown total number of events or numbers we get n(E) = 6

because we can get possible numbers = 6

Now when throw a die and get a number which is non prime ( a number divisible by self and by other number) the preferred events will be n(S) = 2 (number 4 and 6).

So probability of getting a non prime number $P=\frac{n(E)}{n(S)}=\frac{2}{6}=\frac{1}{3}$

Therefore answer is $\frac{1}{3}$

Answer 2

The correct answer is 1/3.

Explanation:
If a number is non-prime, that means that it is divisible by more than 1 and itself. The only numbers that this is true for on a die are 4 and 6.

There are two possible outcomes out of a total of 6 outcomes on a die, so the probability is 2/6=1/3.