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Natalija [7]
3 years ago
13

Help I need help please

Mathematics
1 answer:
morpeh [17]3 years ago
4 0
I can’t seem to see the image weird sorry
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HELPPP!! PLS!!! ❤❤ ​
VashaNatasha [74]

Answer:

The first five belong in the left most group of 1/6 =  1/3÷2

The sixth (right) one belongs in the middle group of 1/9 = 1/3÷3

Step-by-step explanation:

5 0
3 years ago
Point p’ (1,5) is the image of p (-3,1) under a translation<br><br> khan academy
GarryVolchara [31]

Answer:

<h2>X = \frac{-x}{3}</h2><h2>Y = 5y.</h2>

Step-by-step explanation:

We need to find the translation for which, (-3, 1) becomes (1, 5).

-3 will become 1, if it is divided by -3.

Hence, the translation for x axis is X = \frac{-x}{3}.

1 will become 5, when it is multiplied by 5.

Hence, The translation for y axis is Y = 5y.

6 0
3 years ago
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If d= 2, what is the value of 8/(4-d)? A.1 <br>B. 4/3<br>C. 4<br>D. 0​
zimovet [89]
8/ (4-2)
8/2
Answer 4 (C)
3 0
3 years ago
A rectangular park of length 60 m breadth 50 m encloses w volleyball court of length 18 m and breadth 10 m. Find the area of the
Zanzabum

Given

A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.

To find:

The area of the park excluding the court at the rate of Rs 110 per square meter.​

Solution:

Area of a rectangle is:

Area=length \times breadth

Area of whole park is:

A_1=60 \times 50

A_1=3000

Area of volleyball court is:

A_2=18 \times 10

A_2=180

Now, the area of the park excluding the court is:

A=A_1-A_2

A=3000-180

A=2820

Therefore, the area of the park excluding the court is 2820 square meter.

4 0
3 years ago
How to do this question -14=k-4
Furkat [3]

Answer: hope this helps .

Step-by-step explanation:

3 0
3 years ago
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