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iogann1982 [59]
3 years ago
6

A set of weights includes a 5 lb barbell and 4 pairs of weight plates. Each pair of

Mathematics
1 answer:
Zina [86]3 years ago
5 0

Answer:

The answer to this question would be B:

Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.

Hope this reached you well :)

Step-by-step explanation:

20 = weight of the weight plates

x = amount of weight plates.

5 = weight of the barbell

f(x) = 20(0) + 5 = 5

f(x) = 20(1) + 5 = 25

f(x) = 20(2) + 5 = 45

f(x) = 20(3) + 5 = 65

f(x) = 20(4) + 5 = 85

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Answer:

z=\frac{0.872 -0.9}{\sqrt{\frac{0.9(1-0.9)}{180}}}=-1.252  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% the proportion of students who came from Arkansas or a bordering state is not significantly lower than 0.9

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Step-by-step explanation:

Data given and notation n  

n=180 represent the random sample taken

X=157 represent the students who came from Arkansas or a bordering state

\hat p=\frac{157}{180}=0.872 estimated proportion of students who came from Arkansas or a bordering state

p_o=0.9 is the value that we want to test

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Confidence=90% or 0.90

z would represent the statistic (variable of interest)

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Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher or not than 0.9.:  

Null hypothesis:p\geq 0.9  

Alternative hypothesis:p < 0.9  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.872 -0.9}{\sqrt{\frac{0.9(1-0.9)}{180}}}=-1.252  

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The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

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