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jek_recluse [69]
3 years ago
7

I will give BRAINLIEST to whoever is correct.

Mathematics
1 answer:
Naily [24]3 years ago
4 0
The answer would be C. Hope this helps :)
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Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)
Elis [28]

Answer:

Distance between point (3,4) and midpoint of line joining (8,10) and (4,6) = 5 units.

Step-by-step explanation:

Given:

Points:

A(3,4)\\B(8,10)\\C(4,6)

To find distance from point A to midpoint of  BC.

Midpoint M of BC:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\

M=(\frac{8+4}{2},\frac{10+6}{2})\\     [Plugging in points B(8,10)\ and\ C(4,6)]

M=(\frac{12}{2},\frac{16}{2})\\

M=(6,8)\\

Distance between A and M:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

D=\sqrt{(6-3)^2+(8-4)^2} \\   [Plugging in points A(3,4)\ and\ M(6,8)]

D=\sqrt{(3)^2+(4)^2} \\

D=\sqrt{9+16} \\

D=\sqrt{25} \\

D=\pm5

Since distance is always positive ∴ D= 5 units

4 0
3 years ago
A women invest 806.68in a saving account that pays 5.25% annually how much is in the account at the end of the year
Brut [27]
Simple interest= prt
=806.68 (.0525)(1)
=42.35

Balance=investment + interest earned
806.68+42.35=$849.03
3 0
3 years ago
How do you put 15/60 in simplest form?
bulgar [2K]
First u put 15/60 in fraction form(15over60)u find out the multiple that they have incommon which is 15 you divide your denominator and your numerator by 15 because that was the common multiple.so now u divide,(15 divided by 15=1)then divide(60 dived by 15=4)so now your answer is 1/4.I HOPE THIS HELPS
5 0
3 years ago
Suppose you are going to graph the data in the table. Minutes Temperature (°C) 1 -2 2 5 3 10 4 24 5 35 6 22 7 6 8 -8 What data s
Temka [501]

Answer:

It should be represented Minutes on the x-axis, and Temperature (°C) on the y-axis, and the axis increment on the x-axis sould be 1, and on the y-axis should be 5

Step-by-step explanation:

Minutes     Temperature (°C)

     1                   -2

     2                   5

     3            10

     4            24

     5            35

     6            22

     7             6

     8            -8

6 0
3 years ago
Mr. Robredo is building a fence around a rectangular region with 36 feet of fencing. The area of the rectangular region is 65 sq
Dima020 [189]
The length and width are 5&13
4 0
2 years ago
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