All categories

3 years ago

Express the following in exponential notation: (-13) X (-13). 35 times

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

Answer:

$(-13) * (-13) = (-13)^{2}$

$35 * 35 = 35^{2}$

Step-by-step explanation:

Given

$(-13) * (-13)$

Required

Express as an exponential notation

$(-13) * (-13)$

Apply the following law of indices

$x^a * x^b = x^{a+b}$

This gives:

$(-13) * (-13) = (-13)^{1+1}$

$(-13) * (-13) = (-13)^{2}$

<em>The second complete is incomplete; However, I'll assume it is: 35 times 35</em>

$35 * 35$

Using the same law applied in (1) above:

$35 * 35 = 35^{1+1}$

$35 * 35 = 35^{2}$

You might be interested in

I GIVE BRAINLIEST <br> Can someone help me on both of they pls.

Igoryamba

Answer:for the first one its 3 y he second one is 8 and the last one is 5 the second one isn7 and the third one is 2

Step-by-step explanation:

8 0

3 years ago

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

kramer

Answer:

(a)

$\bar x = 0.0075$

$s = 0.0049$

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

$n = 8$

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}$

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}$

$\bar x = \frac{0.06}{8}$

$\bar x = 0.0075$

Next, calculate the standard deviation (s).

This is calculated using:

$s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}$

So, we have

$s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}$ $s = \sqrt\frac{0.00019}{8}$