<span>x1+x2+x3=0 if x1,x2,x3 > -5? and the solutions are integer x1= - 4 and x2+x3=4 we count (-4;4;0), (-4;0;4), (-4;3;1), (-4;1;3), (-4; 2;2), (-4;2;2) x1= -3 and x2+x3=3 we count (-3; 0;3), (-3;3;0), (-3;1;2), (-3;2;1) x1= -2 and x2+x3=2 we count (-2;0;2). (-2;2;0), (-2;1;1) x1= -1 and x2+x3=1 we count (-1;0;1), (-1;1;0) x1=0 and (0;0;0), (0;1;-1), (0;-1;1) There are 42 solutions Have fun</span>
You can multiply 16 times what equls 88 and then divide by 4 much more simple than it sounds and also your in high school and u cant solve this problem
