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asambeis [7]
2 years ago
5

How many integer solutions are there to the equation x1+x2+x3=0 if x1,x2,x3 > -5?

Mathematics
1 answer:
anyanavicka [17]2 years ago
4 0
<span>x1+x2+x3=0 if x1,x2,x3 > -5? 
and the solutions are integer
x1= - 4 and x2+x3=4 we count (-4;4;0), (-4;0;4), (-4;3;1), (-4;1;3), (-4; 2;2), (-4;2;2)
x1= -3 and x2+x3=3 we count (-3; 0;3), (-3;3;0), (-3;1;2), (-3;2;1)
x1= -2 and x2+x3=2 we count (-2;0;2). (-2;2;0), (-2;1;1)
x1= -1 and x2+x3=1 we count (-1;0;1), (-1;1;0)
x1=0 and (0;0;0), (0;1;-1), (0;-1;1)
There are 42 solutions
Have fun</span>
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