Alex read 4 pages in a book in 6 minutes. How long would you expect him to take to read 6 pages at this rate?

Please help me on this will give you brainliest!

kirill [66]

Answer:

∠V = 33°

∠W = 90°

∠X = 57°

Step-by-step explanation:

In a right triangle, the sum of the acute angles is 90 degrees

(2x+3) + (3x+12) = 90

combine like terms

5x + 15 = 90

5x = 75

x = 15

∠V = 2x+3, x=15

2(15) + 3

30 + 3

33°

∠X = 3x+12, x=15

3(15) + 12

45 + 12

57°

8 0

3 years ago

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Why is it important to choose a bank that is a member of the FDIC?

Anettt [7]

Why is it important to choose a bank that is a member of the FDIC?

The FDIC is a government bureau that insures the money that customers deposit in the bank, so your money is safer in an FDIC bank.

Hope This Helped! :3

8 0

3 years ago

Read 2 more answers

There are 15 people on a basketball team, and the coach needs to choose 5 to put into

snow_lady [41]

Answer:

The coach can do this in 3,003 ways

Step-by-step explanation:

Here, the coach needs to select a team of 5 from a total of 15 players

Mathematically, the number of ways this can be done is simply 15 C5 ways

Generally, if we are to select a number of r items from n items, this can be done in nCr ways = n!/(n-r)!r!

Applying this to the situation on ground, we have;

15C5 = 15!/(15-5)!5! = 15!/10!5! = 3,003 ways

3 0

3 years ago

(1+5i) + (-8+i) ? Need answer and steps

Shtirlitz [24]

Answer:

6 $\sqrt{-1}$ -7

Step-by-step explanation:

simplyifying this we get

1+5i-8+i

= 6i-7

I am assuming the i you are talking about here is the sqrt of negative one so that would be 6 $\sqrt{-1}$ -7

7 0

3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0

3 years ago