All categories

3 years ago

What is the value of c such that x^2+14x+c is a perfect-square trinomial?

Mathematics

1 answer:

polet [3.4K]3 years ago

4 0

Answer: 49

Step-by-step explanation:

a=1 ,b=14, c=?

b^2-4ac =0

(14)^2-4(1)(c)=0

196-4c=0

196=4c

c=49

Check:

(x)^2+2(x)(7)+(7)^2

x^2+14x+49

(x+7)^2

You might be interested in

ANSWER PLZ QUICK AND FAST

kotykmax [81]

Hi!

The answer is C. It is a numerical expression because it contains only numbers and operation symbols.

4 0

3 years ago

Two students, Matt and Billy , each calculated the volume of a spherical ball with a dime tee of 15 centimeters. Their work is s

Aleksandr-060686 [28]

Answer:

Matt ;

Used diameter of the ball instead of Radius

Step-by-step explanation:

The volume of a sphere is given as :

4/3πr³

Radius, r = diameter / 2

Given that, the diameter = 15 cm ; The Radius = 15 / 2 = 7.5 cm

Matt made an error in his calculation by failing to covert the value of the diameter given to Radius.

By dividing the diameter by 2 = 15 / 2 = 7.5, we obtain the Radius, which is what Billy did in her own calculation.

7 0

3 years ago

Multiplying by which number is equivalent to finding 15%?

Ahat [919]

.15 is your answer, seeing as .15 is equivalent to 15%

3 0

3 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. if necessary, use / for the fraction bar(s).

Marrrta [24]

Answer:

$\frac{11}{12} - \frac{1}{3} = \frac{7}{12}$

Step-by-step explanation:

Given

See attachment for question

Required

Solve

We have:

$\frac{11}{12} - \frac{1}{3}$

Take LCM and solve

$\frac{11}{12} - \frac{1}{3} = \frac{11 - 4}{12}$

$\frac{11}{12} - \frac{1}{3} = \frac{7}{12}$

4 0

3 years ago

Math again yay!...Ew math

Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

$f(x)=x^2$

New function:

$g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2$

Transformations:

For a > 0

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}$

$\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}$