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2 years ago

Two patrol boats leave Cape May at the same time, the same speed, but on different bearings. One has bearing 41°45

Mathematics

1 answer:

VMariaS [17]2 years ago

8 0

Based on the information given, the computation shows that the distance between them is 2.47 miles.

<h3>Solving the distance.</h3>

Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.

The other has bearing 59°13'. This will be:

= 59° + (13/60) = 59° + 0.22 = 59.22°.

The difference of the angles will be:

= 59.22° - 41.75°

= 17.47°

Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:

c² = a² + b² - 2ab cos 17.47°

c² = 20² + 20² - (2 × 20 × 20 × 0.19)

c² = 6.07459

c = 2.47

Learn more about distance on:

brainly.com/question/2854969

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Write 560,000 in scientific notation.

BabaBlast [244]

Answer:

5.6 * 10^5

Step-by-step explanation:

If 5 is your number, the power of 10 has to be how many digits come after it. 5<u>60000</u>. Five digits come after, making that your power of 10.

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4 years ago

How do you solve an inequality like this/<br><br> x-2/x+16 ≥ 0

neonofarm [45]

$\bf \cfrac{x-2}{x+16}\ge 0\implies \stackrel{cross-multiplying}{x-2\ge (x+16)0}\implies x-2\ge 0\implies x\ge 2$

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3 years ago

Anyone can do this please if you can do all of it of you can I'm really bad at math

Vilka [71]

Im Gonna Do 14 And 15.

14:
3/4 (9/12) + 1/3 (4/12) = 13/12
4/5 (16/20) - 1/4 (5/20) = 11/20

15:
-15 < -6
-31 < -19
-5 < 20
-21 < -15
0 < 22
-57 < -26
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-124 < 30
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Hope This Helps!

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3 years ago

Historical data indicates that only 20% of cable customers are willing to switch companies. If a binomial process is assumed, th

Natasha_Volkova [10]

Answer:

a. The probability is 0.735

b. The probability is 0.6296

c. The probability is 0

Step-by-step explanation:

If we assume a binomial process, the probability that x customer are willing to switch companies is:

$P(x)=nCx*p^{x}*(1-p)^{n-x}$

nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Where n are the 20 cable customers and p is the probability 0.2 that the cable customer are willing to switch companies.

Then, P(x) is:

$P(x)=20Cx*0.2^{x}*(1-0.2)^{20-x}$

The probability that between 2 and 5 (inclusive) customers are willing to switch companies is:

P(2≤x≤5) = P(2) + P(3) + P(4) + P(5)

Where P(2), P(3), P(4) and P(5) are equal to:

$P(2)=20C2*0.2^{2}*(1-0.2)^{20-2}=0.1369$

$P(3)=20C3*0.2^{3}*(1-0.2)^{20-3}=0.2054$

$P(4)=20C4*0.2^{4}*(1-0.2)^{20-4}=0.2182$

$P(5)=20C5*0.2^{5}*(1-0.2)^{20-5}=0.1745$

So, P(2≤x≤5) is:

P(2≤x≤5) = 0.1369 + 0.2054 + 0.2182 + 0.1745 = 0.735

At the same way, the probability that less than 5 customers are willing to switch is:

P(x<5)=P(0)+P(1)+P(2)+P(3)+P(4)

P(x<5)=0.6296

Finally, the probability that more than 16 customers are willing to switch is:

P(x>16)=P(17)+P(18)+P(19)+P(20)

P(x>16)=0

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4 years ago

Help pls :) 10 points

Alexeev081 [22]

Answer:

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Step-by-step explanation:

Since Sq root of 64 = 8 and Sq root of 81 = 9 it is known that sq root of 66 is between 8 and 9

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3 years ago