Answer:
$1,391.25
Step-by-step explanation:
Noon would be 12:00 PM which would be 4 hours ahead of 8:00 AM
We subtract $8,821 by $3,256 to get the amount earned between 8:00 AM and 12:00 PM
$8,821 - $3,256
= $5,565
The find the average taken in within those 4 hours we will have to divide the money earned by the hours
$5,565/4
= $1,391.25
Answer:
b) observing every person walking down Main Street at 5 p.m. one evening to determine the percentage of people who wear glasses.
d) taking a poll in the lunch room (where all students currently have to eat lunch) to determine the number of students who want to be able to leave campus during lunch.
Step-by-step explanation:
These are the two options that are most likely to give you a sample that fairly represents the population. In the first case, the sample that you obtain is likely to be a good representation because Main Street is a road where a great variety of people walk. Moreover, 5 pm is also a time that will allow you to see a great number of different people. The second answer will also give you a good sample, as the poll would include all students in the lunch room, which is all students in the school (the whole population).
Answer:
yes
Step-by-step explanation:
By pythagoras' theorem,
97^2 = 9409
65^2 + 72^2 = 9409
since 65^2 + 72^2 = 97^2, the triangle is a right angled triangle
This is a question on Pythagoras theorem. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)
Answer:
6. r = 21 cm
7. A = 155.5 m²
Step-by-step explanation:
7: Formula for arc length is;
S = (θ/360) × 2πr
We are given;
S = 51 cm
θ = 139°
Thus;
51 = (139/360) × 2π × r
Making r the subject;
r = (51 × 360)/(2π × 139)
r ≈ 21 cm
8) Area of sector is gotten from the formula;
A = (θ/360) × πr²
A = (220/360) × (π × 9²)
A = 155.5 m²
-4^2 is the same as -4*-4
-4*-4=16
-4^2= 16
-4^2 is the exponent.
I hope this helps!
~kaikers
