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horsena [70]
2 years ago
12

a sock drawer has 6 red socks and 4 blue socks. what is the probability or picking two blue socks without replacement

Mathematics
1 answer:
nalin [4]2 years ago
8 0
It is 4/10 times 3/9 which is 12/90.12/90 is equivalent to 4/30, or 2/15 chance.
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Need help finding n forgot how to do this
andreyandreev [35.5K]

Answer:

n  =                                    3\sqrt{2}

There are two best ways to solve this.

using cosine method:

cos(n) =  \frac{adjacent}{hypotenuse}

cos(60) = \frac{adjacent}{6\sqrt{2} }

adjacent,n = cos(60) * 6\sqrt{2}

n  =                                    3\sqrt{2}

using sine method:

sin(n) = \frac{opposite}{hypotenuse}

sin(30)=  \frac{n}{6\sqrt{2} }

n  = sin(30) * 6\sqrt{2}

n = 3\sqrt{2}

There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~

5 0
1 year ago
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the perimeter of a rectangle swimming pool is 486 feet. The width of the pool is 35 feet less than the length. Find the length a
statuscvo [17]

Answer:

Length: 139 feet

Width: 104 feet

Step-by-step explanation:

The formula for the perimeter of a rectangle can be given by P = 2l + 2w. We are given the perimeter of the pool along with the width.

P = 486

w = l - 35

From here, all we have to do is plug back into the original formula:

486 = 2l + 2(l - 35)

Which can be further simplified as:

486 = 2l + 2l - 70

486 = 4l - 70

From here, all we have to do is add 70 to both sides of the equation and divide by four:

556 = 4l

139 = l

To make sure that this answer is accurate, we can find that the width of the rectangle should then be 104 (given by 139 - 35). All we have to do is plug back into the original equation:

P = 2l + 2w

P = 2(139) + 2(104)

P = 278 + 208

P = 486

And the substitution works, so the length of the rectangle would be 139 feet and the width would be 104 feet.

5 0
2 years ago
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I need help on 10,11,12, and 13 plz help me
Mila [183]
10. 14
       2 * 7 <==

11. 12
      6 * 2
      2 * 3 * 2 = 2^2 * 3 <==

12. 15
      3 * 5 <==

13. ur gonna have 3 tables that each have 4 chairs
7 0
3 years ago
An archery target consists of a circular bull's-eye with radius x, surrounded by four rings with width y. What is the area of th
amid [387]
<span>given:
   bull's eye radius= x
 width of surrounding rings=y

   solution:
   Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring =Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
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 hence the area of the outermost ring in terms of x and y is Ď€(2xy+7y^2).</span>
4 0
3 years ago
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