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solong [7]
2 years ago
12

Help needed here please help

Mathematics
1 answer:
bazaltina [42]2 years ago
4 0

Answer:

g(f(x))= (x+3)(x+3)

Step-by-step explanation:

f(x) =x² + 6x +7

g(x)= x + 2

1st Step: Substitute the x in g(x) =x + 2 by the value of f(x)

g(f(x))= (x² + 6x +7) + 2

g(f(x))= x² + 6x + 9

2nd Step: Simplify

g(f(x))= x² + 6x + 9

g(f(x))= (x+3)(x+3)

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The answer is right above me yw lol
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3 years ago
Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?
vovangra [49]

Answer: x≤ -0.5

Step-by-step explanation:  Graph the two lines or solve for x:

2x – 6 ≥ 6(x – 2) + 8

2x – 6 ≥ 6x – 12 + 8

2x – 6 ≥ 6x – 4

-4x  ≥  2

  x  ≤  -1/2  [Inequality is reversed when multiplying or dividing by a negative number]

The number line is anything less than or equal to - 1/2

Or one can plot each side of the inequality and note the interception point (x = -(1/2)).

4 0
3 years ago
A sample of an unknown liquid has a volume of 24.0 mL and a mass of 6 g. What is its density?
Furkat [3]

Answer:

Hey there!

Density = Mass/Volume

Mass= 6g

Volume=24 mL, which is 24 cm^3

Density= 6g/24 cm^3

Density=0.25 g/cm^3

Let me know if this helps :)

5 0
3 years ago
Read 2 more answers
Find the perimeter of the figure?
zhannawk [14.2K]

Answer:

36

Step-by-step explanation:

9+9+9+9=36

8 0
3 years ago
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Jon recently drove to visit his parents who live 280 miles away. On his way there his average speed was 9 miles per hour faster
Luba_88 [7]

Answer:

11 mph and 20 mph

Step-by-step explanation:

Represent his average speed going by r1 and his average speed returning by r2.  We know that r1 = r2 + 9.

Recall that distance = rate times time, so time = distance / rate.

Time spent going was (280 mi) / r1, or (280 mi) / (r2 + 9 mph).

Time spend returning was (280 mi) / r2.

The total time was 14 hrs, so (280 mi) / (r2 + 9 mph) + (280 mi) / r2 = 14 hrs

Note that there is only one variable here:  r2.  Find r2, and then from r2, find r1:

Dividing all 3 terms by 14 hrs yields:

  20            20

---------- + ----------- = 1

r2 + 9         r2

The LCD here is r2(r2 + 9).  Thus, we have:

      20r2                    (r2 +  9)(r2)

------------------- = 1 or  ------------------

 (r2 +  9)(r2)               (r2 +  9)(r2)

Then 20(r2) = (r2)^2 + 9(r2).  This is reducible by dividing all terms by r2:

20 = r2 + 9, or 11 = r2.  Then r1 = 11 + 9, or 20.

The two rates were 11 mph and 20 mph.

8 0
3 years ago
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