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4 years ago

Multiply and simplify. Show work to earn BRAINLIEST ANSWER ASAP!98 POINTS (7x-6)(3x^2-4x+5)

Mathematics

1 answer:

zavuch27 [327]4 years ago

3 0

Multiply each term in the first set of parentheses by each term in the second set, then combine like terms.

7x x 3x^2 = 21x^3

7x x -4x = -28x^2

7x x 5 + 35x

-6 x 3x^2 = -18x ^2

-6 x -4x = 24x

-6 x 5 = -30

Combine like terms to get:

21x^3 - 46x^2 + 59x - 30

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f(x) = 20(1.5)x. Let your dependent variable in the function be y. Write the function that models the independent variable in te

mars1129 [50]

Answer:

$x=log_{1.5}(\frac{y}{20})$

Step-by-step explanation:

Considering the function:

$f(x) = 20\, (1.5)^x$

The independent variable is "x" and we are asked to model it in terms of the variable "y":

$f(x) = 20\, (1.5)^x\\y=20\, (1.5)^x$

Then, in order to solve for x (which resides in the exponent), we need to use the logarithm function.

Since the base of the exponent is 1.5, we need to use the logarithm base 1.5, to lower that exponent "x":

$y=20\, (1.5)^x\\\frac{y}{20} =(1.5)^x\\log_{1.5}(\frac{y}{20}) =x\\x=log_{1.5}(\frac{y}{20})$

6 0

3 years ago

The lowest altitude of an altocumulus cloud is about 3^(8) ft. The highest altitude of an altocumulus cloud is about 3 times the

Alinara [238K]

3(3^8) this is how you write it as power. however if you simplify it will be 19683 ft

3 0

4 years ago

Read 2 more answers

187÷11 quanto es eso

RideAnS [48]

18/11 = 1 remainder 7

77/11=7

Answer <em>17</em>

3 0

4 years ago

Read 2 more answers

An urn contains 12 balls, of which 4 are white.

wel

Answer:

a) $\frac{1}{3}$

b) $\frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...$

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let $A_i\,,\,B_i\,,\,C_i$ denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: $P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}$

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: $P(A_1)=\frac{4}{12}=\frac{1}{3}$

If A lost and B wins: $P\left ( B_1|A_1^{c} \right )=\frac{4}{11}$

If A and B lost and C wins: $P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}$

and so on....

4 0

4 years ago

Find the ratio of Rs 20 and 900

Tema [17]

Answer:

1 : 45

Step-by-step explanation:

Given

Rs 20 and 900 ( divide both by 20 )

= 1 : 45

8 0

3 years ago