How do you find the base area of a rectangular prism and a cylinder? Please help

Mathematics

1 answer:

Pani-rosa [81]4 years ago

3 0

Answer:

See explanation.

Step-by-step explanation:

The 'base' of a rectangular prism refers to only one side of the rectangular prism, which is a rectangle.

The formula for the area of a rectangle is as follows:

$A=lw$

Where A = area, l = length, and w = width.

The 'base' of a cylinder refers to only one side of the cylinder, which is a circle.

The formula for the area of a circle is as follows:

$A=\pi r^2$

Where A = area and r = radius.

Just in case you typed your question incorrectly and were asking for surface area, here is the formula for surface area for both as well:

Rectangular prism: $A=2(wl+hl+hw)\\$

Cylinder: $A=2\pi rh+2\pi r^{2}$

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Ruth found 37 tickets for $7. Please help Ruth by figuring out the ratio. (round to 2 decimal places)

Amanda [17]

Answer:

Ratio of ticket to its price is 1 : 0.189.

Step-by-step explanation:

Here, the cost of 37 tickets = $7

Let us find the unit cost of the ticket.

$\textrm{Unit Price } = \frac{\textrm{Total Price of n units}}{\textrm{n}}$

$\implies U = \frac{7}{37}=0.189$

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3 years ago

X(2x-5) = 12<br><br> How to solve for x?

vlabodo [156]

Answer:

$x=4,\:x=-\frac{3}{2}$

Step-by-step explanation:

$x\left(2x-5\right)$

Apply the distributive law.

$=x\cdot \:2x-x\cdot \:5$
$=2x^2-5x$
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Subtract 12 from both sides.
$2x^2-5x-12=12-12$
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Now, apply the quadratic formula.
$x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-12\right)}}{2\cdot \:2}$
$x_{1,\:2}=\frac{-\left(-5\right)\pm \:11}{2\cdot \:2}$
Separate the solutions.
$x_1=\frac{-\left(-5\right)+11}{2\cdot \:2},\:x_2=\frac{-\left(-5\right)-11}{2\cdot \:2}$
Simplify.
$x=4,\:x=-\frac{3}{2}$